4*x^2*3.14=113.04

Solution for 4*x^2*3.14=113.04 equation:

4x^2*3.14=113.04

We move all terms to the left:

4x^2*3.14-(113.04)=0

We add all the numbers together, and all the variables

4x^2*3.14-113.04=0

Wy multiply elements

12.56x^2-113.04=0

a = 12.56; b = 0; c = -113.04;
Δ = b2-4ac
Δ = 02-4·12.56·(-113.04)
Δ = 5679.1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5679.1296}}{2*12.56}=\frac{0-\sqrt{5679.1296}}{25.12}
=-\frac{\sqrt{}}{25.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5679.1296}}{2*12.56}=\frac{0+\sqrt{5679.1296}}{25.12}
=\frac{\sqrt{}}{25.12}
$